import Foundation
let pattern = #"(?<!\s)[\u00ad\u2212\u002D\u058A\u05BE\u1400\u1806\u2010-\u2015\u2E17\u2E1A\u2E3A\u2E3B\u2E40\u301C\u3030\u30A0\uFE31\uFE32\uFE58\uFE63\uFF0D\u002D\u058A\u05BE\u1806\u2010\u2011\u2012\u2013\u2014\u2015\u2E3A\u2E3B\uFE58\uFE63\uFF0D\u10EAD]|[\u00ad\u2212\u002D\u058A\u05BE\u1400\u1806\u2010-\u2015\u2E17\u2E1A\u2E3A\u2E3B\u2E40\u301C\u3030\u30A0\uFE31\uFE32\uFE58\uFE63\uFF0D\u002D\u058A\u05BE\u1806\u2010\u2011\u2012\u2013\u2014\u2015\u2E3A\u2E3B\uFE58\uFE63\uFF0D\u10EAD](?!\s)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"a-b - -s d-"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression