import Foundation
let pattern = #".*Function=\"([^\"]*).*"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
[1] ID=Gfo_R000001;Source=ENST00000513418;Function="SMAD5";
[2] ID=Gfo_R000002;Source=ENSTGUT00000017468;Function="CENPA";
[3] ID=Gfo_R000003;Source=ENSGALT00000028134;Function="C1QL4";
[4] ID=Gfo_R000004;Source=ENSTGUT00000015300;Function="";
[5] ID=Gfo_R000005;Source=ENSTGUT00000019268;Function="";
[6] ID=Gfo_R000006;Source=ENSTGUT00000019035;Function="";
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"\1"#
let result = regex.stringByReplacingMatches(in: testString, range: stringRange, withTemplate: substitutionString)
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression