import Foundation
let pattern = #"(?:^|\n)(\d{4}(?:-\d{2}){2} (?:\d{2}:){2})\d{2}\.\d{3}( [+-]\d{2}:\d{2} )\[\d+\]( - Starting)[^\n]*(?=(?:\n\1\d{2}\.\d{3}\2\[\d+\][^\n]*)*\n\1\d{2}\.\d{3}\2\[\d+\]\3[^\n]*)|(?<=(?:^|\n)(\d{4}(?:-\d{2}){2} (?:\d{2}:){2})\d{2}\.\d{3}( [+-]\d{2}:\d{2} )\[\d+\]( - Starting)[^\n]*(?:\n\4\d{2}\.\d{3}\5\[\d+\][^\n]*)*)\n\4\d{2}\.\d{3}\5\[\d+\]\6[^\n]*"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
2019-10-31 05:49:52.416 +10:00 [1] - Starting
2019-10-31 05:49:53.416 +10:00 [2] - not starting
2019-10-31 05:49:53.416 +10:00 [2] - Starting
2019-10-31 05:49:53.416 +10:00 [3] - Starting
2019-10-31 06:53:58.416 +10:00 [1] - Starting
2019-10-31 06:53:58.416 +10:00 [1] - Identical but not "starting"
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression