re = /\b(
# MAC address like xx:xx:xx:xx:xx:xx
[0-9a-f]{2}:[0-9a-f]{2}:[0-9a-f]{2}:[0-9a-f]{2}:[0-9a-f]{2}:[0-9a-f]{2}
|
# MAC address like xx-xx-xx-xx-xx-xx
[0-9a-f]{2}-[0-9a-f]{2}-[0-9a-f]{2}-[0-9a-f]{2}-[0-9a-f]{2}-[0-9a-f]{2}
|
# MAC address like xxxx.xxxx.xxxx
[0-9a-f]{4}\.[0-9a-f]{4}\.[0-9a-f]{4}
|
# IPv4 address in dotted-quad format
# Not a lot of value for our needs in checking range of each octet
# Need to be more mindful of performance here anyway.
\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}
)\b/ix
str = '192.168.1.2
10.0.0.0
ff:ff:ff:ff:ff:ff
FF-FF-FF-FF-FF-FF
FFFF.FFFF.FFFF
ffff.ffff.ffff
blah127.0.0.1haha
foo127.0.0.1
'
subst = '\\1'
result = str.sub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html