import Foundation
let pattern = #"^(?:\+44\s?|0)[1238]\d\s?(?:\d\s?){7,8}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = ##"""
# Standard
01386 444400
01386444400
+441386444400
+44 1386 444400
+44 1386444400
# 5 Digit
01386 41204
0138641204
+44138641204
+44 1386 41204
+44 138641204
# 3 Digit area codes (e.g. London)
+442074343046
02074343046
020 74343046
020 7434 3046
# 4 Digit area codes (e.g. Leeds)
+441133971337
01133971337
0113 3971337
# Commercial
08451772266
0845 1772266
# Mobile number (should not match)
07999888777
+447999888777
07999 888 777
+44 7999888777
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression