import Foundation
let pattern = #"(\n|\s)(?:(?:\+?(\d{1}|\d{2}|\d{3})\s*)\s*(?:\(\s*(\d{1}|\d{2}|\d{3})\s*\)|(\d{1,3}))\s*\-?(?:\(\s*(\d{1,3})\s*\)|(\d{3}))\s*\-?(?:\d{2}\s*\-?\d{2}))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
+79996364778 rus
8 (918) 373-6633 rus
+1 650-798-2800 usa
8(949)373-66-55 rus
+7 (961) 859-56-19 rus
+1 205-635-1136 usa
+22(909)333 4334
+7(985)5310868
+79855310868
88008454545
+55 11 99999-5555 Brazil
+593 7 282-3889 Ecuador
(+44) 0848 9123 456 UK
+1 284 852 5500 BVI
+1 345 9490088 Grand Cayman
+32 2 702-9200 Belgium
+65 6511 9266 Asia Pacific
+86 21 2230 1000 Shanghai
+9124 4723300 India
+821012345678 South Korea
And for your extension pleasure
+55 11 99999-5555 ramal 123 Brazil
+55 11 99999-5555 foo786544 Brazil
(?!\b(0)\1+\b)(\+?\d{1,3})\s?\(?\d{3}\)?\s?([. -]?)\d{3}\3\d{4}
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression