import Foundation
let pattern = #"((?<=^|\s)([1-9]?[0-9]?[0-9]?((?<!0|^00|\s00|^000|\s000|^0\d{0,2}|\s\d{0,2})[0-9]|[1-9]))\/(0[13456789]|1[0-2])\/(0[1-9]|1[0-9]|2[0-9]|3[0-1])\s(2[0-3]|1[0-9]|0[0-9])\:(0[0-9]|[1-5][0-9])\(\:(0[0-9]|[1-5][0-9])\)(?=$|\s))|((?<=^|\s)([1-9]?[0-9]?[0-9]?[0-9])\/(02)\/(0[1-9]|1[0-9]|2[0-9])\s(2[0-3]|1[0-9]|0[0-9])\:(0[0-9]|[1-5][0-9])\(\:(0[0-9]|[1-5][0-9])\)(?=\s)(?=$|\s))"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression