re = /^[\p{L}\s]+/m
str = 'РПÑАВÂРßÛÑ ÛÑРВßР ÛÑÛÑАÑÛ, 11.22 Ø.Á.
ÛÑРВЛÛÑВ ÛÑßВßДÛÑВßЛ РИÐРÛПÑÑВÛ 11.22 Ã.Ö
ВßÑÛВÂЛÛÑВ ÛÑВÂÛÑВЛß ßРßÂРÑВЛРÛÐßРВ, 11.22 Â.Ö.
ÛÑВÛÑВ ÛßÛßРÑВßРÐ ßТАÛ, 11.22 Ã.Ö.
РÐÑАВПРßÛÑ ÛÑРВßР ÛÑÛÑАÑÛ, 11.22 Ø.р.
ÛÑРВÂÛÑВ ÛÑßВßДÛÑВß РÂПРÛПÑÑВÛ 11.22 Ø.Á.
ВßÑÛВДЛÛÑВ ÛÑВЛÛÑВЛß ßРßЛРÑВЛРÛЛßРВ, 11.22 Ø.Ö.
ÛÑВÛÑВ ÛßÛßРÑВßРÐ ßТАÛ, 11.22 Ï.Á.'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html