import Foundation
let pattern = #"\[(?:\d\.\d*(?:E-\d+)?)(?:, (?:\d\.\d*(?:E-\d+)?))*\]"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"[[[0.6453525160688715, 0.15620941152962334, 0.1874313118193626, 9.991008092716556E-5, 9.991008092716556E-5, 9.991008092716556E-5, 9.991008092716556E-5, 0.01050721017750691, 9.991008092716556E-5], [0.5904776610141782, 0.18175460267577365, 9.991008092716556E-5, 0.22716827582448523, 9.991008092716556E-5, 9.991008092716556E-5, 9.991008092716556E-5, 9.991008092716556E-5, 9.991008092716556E-5]]]"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression