import Foundation
let pattern = #"([0-9]{2})([0-9]*)\.([0-9]+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
[[[379017.735,6940036.7955],[379009.8431,6940042.5761],[379000.4869,6940048.9545],[378991.5455,6940057.8128],[378984.0665,6940066.0744],[378974.7072,6940076.2152],[378962.8639,6940090.5283],[378954.5822,6940101.4028],[378947.9369,6940111.3128],[378941.4564,6940119.5094],[378936.2565,6940128.1229],[378927.6089,6940141.4764],[378919.6611,6940154.0312],[378917.21,6940158.7053],[378913.7614,6940163.4443],[378913.6515,6940163.5893],[378911.4453,6940166.3531],
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"\1.\2\3"#
let result = regex.stringByReplacingMatches(in: testString, range: stringRange, withTemplate: substitutionString)
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression