import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "(\\b\\S+\\b)(?=.*\\b\\1\\b)";
final String string = "123-1 123-2 test-1 test-1 w/e 10/04/20\n"
+ "Company w/e 09/06/20 083020-090620\n"
+ "a/b 01/01\n"
+ "test_1 test_2\n"
+ "a/b a/b\n"
+ "Inv 50049 50049 Inv 50195 PrjPAN02\n"
+ "Inv 51360-1, 51366-7; 51372 Inv 51360-1, 51366-7; 372 PrjPAN02\n"
+ "Inv 51360-1, 51366-7; 51372 51372 Inv 513601, 51366-7; 372 PrjPAN02\n"
+ "55009, 55017, 55022 55001, 55022, 55025\n"
+ "55254, 61 55246,66,69\n"
+ "55733, 41, 44 55727, 45,48\n"
+ "57269, 71,74,75, 57354 57266, 73\n"
+ "57437, 38, 41, 43 57434, 40\n"
+ "w/e 09/20/20 091320-092020";
final String subst = "\"\"";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html