import Foundation
let pattern = #"((?<a>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<b>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<c>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<d>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<e>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<f>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<g>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<h>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))((?<i>(?:\b ?[a-zA-Z0-9]+){0}.*?([a-zA-Z0-9]+) ?))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .dotMatchesLineSeparators)
let testString = #"1234 2D 5678 8765 5678 1111 2222 3333 1"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
if let firstMatch = regex.firstMatch(in: testString, range: stringRange) {
let result: [String] = (1 ..< firstMatch.numberOfRanges).map { (testString as NSString).substring(with: firstMatch.range(at: $0)) }
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression