import Foundation
let pattern = #"(?:(?:0[1-9])|(?:[12][0-9])|(?:3[01])|[1-9])/\\b(?:Jan(?:uary|uar)?|Feb(?:ruary|ruar)?|M(?:a|ä)?r(?:ch|z)?|Apr(?:il)?|Ma(?:y|i)?|Jun(?:e|i)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|O(?:c|k)?t(?:ober)?|Nov(?:ember)?|De(?:c|z)(?:ember)?)\\b/(?>\\d\\d){1,2}:(?!<[0-9])(?:2[0123]|[01]?[0-9]):(?:[0-5][0-9])(?::(?:(?:[0-5]?[0-9]|60)(?:[:.,][0-9]+)?))(?![0-9]) (?:[+-]?(?:[0-9]+))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"[17/Dec/2005:02:40:45 -0500] 192.168.2.10:ossecdb LOG: duration: 0.016 ms statement: SELECT id FROM location WHERE name = 'enigma->/var/log/messages' AND server_id = '1'"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression