import re
regex = re.compile(r"^(?:((?:IT|SM)\d{2}[A-Z]{1}\d{22})|(NL\d{2}[A-Z]{4}\d{10})|(LV\d{2}[A-Z]{4}\d{13})|((?:BG|GB|IE)\d{2}[A-Z]{4}\d{14})|(GI\d{2}[A-Z]{4}\d{15})|(RO\d{2}[A-Z]{4}\d{16})|(MT\d{2}[A-Z]{4}\d{23})|(NO\d{13})|((?:DK|FI|FO)\d{16})|((?:SI)\d{17})|((?:AT|EE|LU|LT)\d{18})|((?:HR|LI|CH)\d{19})|((?:DE)\d{20})|((?:CZ|ES|SK|SE)\d{22})|(PT\d{23})|((?:IS)\d{24})|((?:BE)\d{14})|((?:FR|MC|GR)\d{25})|((?:PL|HU|CY)\d{26}))$", flags=re.IGNORECASE | re.MULTILINE)
test_str = ("SEPA\n"
"SM07U0854009803000030174419\n"
"SI56011006000005649\n"
"ES1321000555370200853027\n"
"CY02002001950000357009822416\n\n"
"NOT SEPA\n"
"SC74NOVH00000021002035257028SCR\n"
"TN5901026067111999766058\n"
"UA123052990004149497803982794")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html