import Foundation
let pattern = #"^(?:[A-Z][AEIOU][AEIOUX]|[B-DF-HJ-NP-TV-Z]{2}[A-Z]){2}(?:[\dLMNP-V]{2}(?:[A-EHLMPR-T](?:[04LQ][1-9MNP-V]|[15MR][\dLMNP-V]|[26NS][0-8LMNP-U])|[DHPS][37PT][0L]|[ACELMRT][37PT][01LM]|[AC-EHLMPR-T][26NS][9V])|(?:[02468LNQSU][048LQU]|[13579MPRTV][26NS])B[26NS][9V])(?:[A-MZ][1-9MNP-V][\dLMNP-V]{2}|[A-M][0L](?:[1-9MNP-V][\dLMNP-V]|[0L][1-9MNP-V]))[A-Z]$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression