re = /^(19|20)\d\d[- \/.](0[1-9]|1[012])[- \/.](0[1-9]|[12][0-9]|3[01])$/m
str = '1900-01-01
1900/01/01
1900-01/01
1900/01-01
1899/12/31
2099/01/01
2100/01/01
2099 12 31
2099/12/31'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html