import Foundation
let pattern = #"\d+\.\d+(\.[\d]+)?"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
/Versionnr: 5.131 //should be 5.13
/Versionname: somename v5.13b1
/Versionnr: 2.0..4 //should be 2.0
/Versionname: another name 2 v2.0.exp.4
/Versionnr: 18.01 //should be 18.0
/Versionname: somename v18.0-ALPHA1
/Versionnr: 7.2.42221..3634639 //should be 7.2.4222
/Versionname: another name v7.2.4222-1.L.3634639
/Versionnr: 5.0.220170112 //should be 5.0.2
/Versionname: somename v5.0.2 build 20170112
/Versionnr: 4.4.0.201701124401 //should be 4.4.0
/Versionname: another name v4.4.0.20170112b4401
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression