# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"(?<!&)(?:\b(?:[a-z]{2,8}\d{0,2})|#[0-9a-f]+);"
test_str = ("I have a huge HTML with several special chars, in the forms or \"�.\n"
"Faulty HEX: #82173333;\n"
"Some of them are wrong, because they lack the initial &.\n\n"
"I would like to search for such wrong spacial chars. I know that I can search all the right special chars by means of the following regex:\n\n"
" \\&(?:[a-z]+|#x?\\d+);\\\n"
"But I'd need a regex useful to search the wrong ones (without the initial &). Can you help me? Thanks in advance\n\n"
"Edit:\n\n"
"As suggested, I post an example. My HTML cointains the following statement:\n\n"
" <![CDATA[<nolink>blablabla blablabla</nolink>]]>nbsp;\n"
"where we have 2 special HTML character:\n"
"divide;\n"
"÷\n"
" \n"
"quot;\n"
"I'm interested in finding the second item, because it is wrong (laking the initial &).\n\n"
"So the output of the requested regex should be: quot;")
matches = re.finditer(regex, test_str, re.MULTILINE | re.IGNORECASE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html