re = /^t=(.* .*) p=(\d+) h=(.*) db=(\w+) u=(\w+) x=(\d+) (\w+:) (.*)/m
str = 't=2020-08-25 15:00:00.000 +03 p=16205 h=127.0.0.1 db=test u=test_app x=0 LOG: duration: 0.011 ms execute S_40: SELECT ID, EKLEME_ZAMANI, EKLEYEN_KULLANICI_ID, GORULME_DURUMU, GUNCELLEME_ZAMANI, GUNCELLEYEN_KULLANICI_ID, IP_ADRESI, ISLEM_ZAMANI, ISLEMI_YAPAN_KULLANICI_ID, METOD, PARAMETRE_JSON, UYGULAMA_ID, VERSIYON, DURUM_ID FROM DB_LOG WHERE (ID = $1)
t=2020-08-25 15:00:00.000 +03 p=16205 h=127.0.0.1 db=test u=test_app x=0 DETAIL: parameters: $1 = \'9187372\'
t=2020-08-25 15:00:00.001 +03 p=36001 h=127.0.0.1 db=test u=test_app x=0 LOG: duration: 0.005 ms bind S_1: COMMIT
t=2020-08-25 15:00:00.001 +03 p=36001 h=127.0.0.1 db=test u=test_app x=0 LOG: duration: 0.004 ms execute S_1: COMMIT
t=2020-08-25 15:00:00.001 +03 p=16205 h=127.0.0.1 db=test u=test_app x=0 LOG: duration: 0.018 ms bind S_41: INSERT INTO DB_LOG (ID, EKLEME_ZAMANI, EKLEYEN_KULLANICI_ID, GORULME_DURUMU, GUNCELLEME_ZAMANI, GUNCELLEYEN_KULLANICI_ID, IP_ADRESI, ISLEM_ZAMANI, ISLEMI_YAPAN_KULLANICI_ID, METOD, PARAMETRE_JSON, UYGULAMA_ID, VERSIYON, DURUM_ID) VALUES ($1, $2, $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13, $14)'
subst = '"\\1","\\2","\\3","\\4","\\5","\\6","\\7","\\8"'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html