Regular Expressions 101

Explanation

Pro

Non-Capturing Group(?:[^\n.!?;:]|[\n.!?;:](?!\s))+

+repeats the group contents below at least once:

1st Alternative[^\n.!?;:]

Negated Character Class[^\n.!?;:]

\na line-feed (newline) character (ASCII 10)

.the literal . (46₁₀ / 56₈ / 2E₁₆)

!the literal ! (33₁₀ / 41₈ / 21₁₆)

?the literal ? (63₁₀ / 77₈ / 3F₁₆)

;the literal ; (59₁₀ / 73₈ / 3B₁₆)

:the literal : (58₁₀ / 72₈ / 3A₁₆)

2nd Alternative[\n.!?;:](?!\s)

Character Class[\n.!?;:]

\na line-feed (newline) character (ASCII 10)

.the literal . (46₁₀ / 56₈ / 2E₁₆)

!the literal ! (33₁₀ / 41₈ / 21₁₆)

?the literal ? (63₁₀ / 77₈ / 3F₁₆)

;the literal ; (59₁₀ / 73₈ / 3B₁₆)

:the literal : (58₁₀ / 72₈ / 3A₁₆)

Negative Lookahead(?!\s)

\sany whitespace character

Character Class[\n.!?;:]+

+matches at least one character from the set below:

\na line-feed (newline) character (ASCII 10)

.the literal . (46₁₀ / 56₈ / 2E₁₆)

!the literal ! (33₁₀ / 41₈ / 21₁₆)

?the literal ? (63₁₀ / 77₈ / 3F₁₆)

;the literal ; (59₁₀ / 73₈ / 3B₁₆)

:the literal : (58₁₀ / 72₈ / 3A₁₆)

Global pattern flags

g modifier: global. Finds all matches instead of stopping after the first

m modifier: multiline. Causes ^ and $ to match the start and end of each line, not only the start and end of the string

Match Information

Detailed match information will be displayed here automatically.

Quick Reference

26 tokens

Regular Expression

(?:[^\n.!?;:]|[\n.!?;:](?!\s))+[\n.!?;:]+

New

It works ok. My problem is when the string has numbers in the thousands marked with a dot that some people use like 1.500. How can alter this so that it only separates the phrases if the punctuation is followed by a space.

Extraction

It works ok. My problem is when the string has numbers in the thousands marked with a dot that some people use like 1.500. How can alter this so that it only separates the phrases if the punctuation is followed by a space.