Regular Expressions 101

Save & Manage Regex

  • Current Version: 1
  • Save & Share
  • Community Library

Flavor

  • PCRE2 (PHP)
  • ECMAScript (JavaScript)
  • Python
  • Golang
  • Java
  • .NET 7.0 (C#)
  • Rust
  • PCRE (Legacy)
  • Regex Flavor Guide

Function

  • Match
  • Substitution
  • List
  • Unit Tests
Sponsors
An explanation of your regex will be automatically generated as you type.
Detailed match information will be displayed here automatically.
  • All Tokens
  • Common Tokens
  • General Tokens
  • Anchors
  • Meta Sequences
  • Quantifiers
  • Group Constructs
  • Character Classes
  • Flags/Modifiers
  • Substitution
  • A single character of: a, b or c
    [abc]
  • A character except: a, b or c
    [^abc]
  • A character in the range: a-z
    [a-z]
  • A character not in the range: a-z
    [^a-z]
  • A character in the range: a-z or A-Z
    [a-zA-Z]
  • Any single character
    .
  • Alternate - match either a or b
    a|b
  • Any whitespace character
    \s
  • Any non-whitespace character
    \S
  • Any digit
    \d
  • Any non-digit
    \D
  • Any word character
    \w
  • Any non-word character
    \W
  • Non-capturing group
    (?:...)
  • Capturing group
    (...)
  • Zero or one of a
    a?
  • Zero or more of a
    a*
  • One or more of a
    a+
  • Exactly 3 of a
    a{3}
  • 3 or more of a
    a{3,}
  • Between 3 and 6 of a
    a{3,6}
  • Start of string
    ^
  • End of string
    $
  • A word boundary
    \b
  • Non-word boundary
    \B

Regular Expression
Processing...

Test String

Code Generator

Language

Generated Code

re = /\b(?<=[A-Z]{2} [–-] ).*?\b[Cc]hapter\b/ str = 'Match unknown number of words that lies between two known patterns I\'m looking to make a regex for use in LibreOffice Writer\'s "Find and Replace" function. LibreOffice version 25.8.4.2. The text I want to search looks like the following. 008 – San Terremoto CA | 010 - Eastern AK – Joe Jolson Chapter | 011 - Doughtown NY | 012 - Copperville AZ | 014 - Gatorville FL | 015 - Swamptown FL | 018 - District of Columbia (DC) | 019 - Central PA | 041 – Stoddard Mill MA - Cpl Mike G. Paulson Chapter |139 - North Pacific Bay WA | 1. Most of the records end with a two-letter U.S. state abbreviation, a space, and a pipe. 2. A number of records end with a two-letter U.S. state abbreviation, a space, a hyphen, a space, unknown number of words separated by spaces, final space, the word "chapter", space, pipe. "Chapter" may or may not be capitalized. In records which match the description in "2." above, I want to match any text which follows the two-letter state abbreviation with a name and the word "chapter". Examples of that text is in boldface type above. I tried a number of things, lastly this: (?<=\\[A-Z\\]{2})\\\\s-\\\\s\\[\\\\w\\]+\\\\s\\[Chapter|chapter\\] and (?<=\\[A-Z\\]{2})\\\\s-\\\\s\\[a-zA-Z\\]+\\\\s\\[Chapter|chapter\\] It has not yet worked. I welcome suggestions. Thank you' # Print the match result str.scan(re) do |match| puts match.to_s end

Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html