re = /(1 ){0,}(\d |\d\d )\2{1,}(1 ){0,}\2{1,}(1 ){0,}/m
str = '3 1 1 4 4 4 4 1 4 4 5 5 1 5 5 6 7 8 1 9 9 9 9 9 9 1 3 4 5 5 1 1 5 5 6 4 4 4 1 7 1 2 2 2 2 2 2 2 1 11 11 11 11 '
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html