import Foundation
let pattern = #"(?:4\s*(?:\d\s*){3}[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){4})|[25]\s*[1-7]\s*(?:\d\s*){2}[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){4}|6\s*(?:0\s*1\s*1|5\s*[0-9]\s*[0-9])[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){4}[- ]*(\d\s*){4}|3\s*[47]\s*(?:\d\s*){2}[- ]*(?:\d\s*){6}[- ]*(?:\d\s*){5}|3\s*(?:0\s*[0-5]|[68]\s*[0-9])\s*\d{1}[- ]*(?:\d\s*){6}[- ]*(?:\d\s*){4}|(?:2\s*1\s*3\s*1|1\s*8\s*0\s*0|3\s*5\s*\d{2})[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){4}[- ]*(?:\d\s*){3,4} "#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression