re = /-\h*(?!.*-)0*(\d+)/m
str = '“2020-07-24 07;17;09 - ABCD - 12345-67890 (14 Main St) - 01 [Declaration 1].png”
“2020-07-24 07;17;09 - ABCD - 12345-67890 (14 Main St) - 02 [Declaration 2].png”
“2020-07-24 07;17;09 - ABCD - 12345-67890 (14 Main St) - 07 [Fire].png”
“2020-07-24 07;17;09 - ABCD - 12345-67890 (14 Main St) - 12 [Fungi etc].png”'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html