const regex = /(Demand.*?\d{2}[\n\r])/g;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('(Demand.*?\\d{2}[\\n\\r])', 'g')
const str = `++ PLANNING ITERATIONS of DEMAND 337 ++
=========================================
Demand: 337 Event: 1189.001 Object/State: 7058/0 Tier: 0 Start: 1608130700 Duration: 90 At: 19-7-2016 16:19:36
Demand: 337 Event: 1190.001 Object/State: 7059/0 Tier: 0 Start: 1608130830 Duration: 330 At: 19-7-2016 16:19:36
Demand: 337 Event: 1191.001 Object/State: 7060/0 Tier: 0 Start: 1608140000 Duration: 360 At: 19-7-2016 16:19:36
++ EVENT PLAN of DEMAND 337 ++
===============================
event_time(1242.001,1,1609070800,1609071430)
event_time(1241.001,1,1609060800,1609061430)
event_time(1240.001,1,1609050800,1609051430)
++ PLANNING ITERATIONS of DEMAND 174 ++
=========================================
Demand: 174 Event: 212.001 Object/State: 6948/0 Tier: 0 Start: 1609010800 Duration: 390 At: 19-7-2016 16:19:38
Demand: 174 Event: 213.001 Object/State: 6949/0 Tier: 0 Start: 1609020800 Duration: 390 At: 19-7-2016 16:19:38
++ EVENT PLAN of DEMAND 174 ++
===============================
event_time(213.001,1,1609020800,1609021430)
event_time(212.001,1,1609010800,1609011430)`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions