Regular Expressions 101

Pro

\ban ASCII word boundary

Non-Capturing Group(?:[a-z](?:[a-z\n\r.:;,?!-]*[a-z])?)

Character Class[a-z]

a-zone character from a (97₁₀) to z (122₁₀) (case insensitive)

Non-Capturing Group(?:[a-z\n\r.:;,?!-]*[a-z])?

?repeats the group contents below at most once:

Character Class[a-z\n\r.:;,?!-]*

*matches any number of characters from the set below:

a-zone character from a (97₁₀) to z (122₁₀) (case insensitive)

\na line-feed (newline) character (ASCII 10)

\ra carriage return (ASCII 13)

.the literal . (46₁₀ / 56₈ / 2E₁₆)

:the literal : (58₁₀ / 72₈ / 3A₁₆)

;the literal ; (59₁₀ / 73₈ / 3B₁₆)

,the literal , (44₁₀ / 54₈ / 2C₁₆)

?the literal ? (63₁₀ / 77₈ / 3F₁₆)

!the literal ! (33₁₀ / 41₈ / 21₁₆)

-the literal - (45₁₀ / 55₈ / 2D₁₆)

Character Class[a-z]

a-zone character from a (97₁₀) to z (122₁₀) (case insensitive)

\ban ASCII word boundary

Global pattern flags

g modifier: global. Finds all matches instead of stopping after the first

s modifier: single line. Allows a dot to match line terminators

i modifier: insensitive. Matches without distinguishing uppercase and lowercase letters

x modifier: extended. Ignores unescaped whitespace and comments outside character classes

Detailed match information will be displayed here automatically.

25 tokens

Regular Expression

\b(?:[a-z](?:[a-z\n\r.:;,?!-]*[a-z])?)\b

New

How do I match text with a regular expres
sion ignoring punctuation and line breaks?
How do I do "find these words pos-
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Extraction

How do I match text with a regular expres
sion ignoring punctuation and line breaks?
How do I do "find these words pos-
sibly separated but some non-alphanumeric characters"?