import Foundation
let pattern = #"[A-z]*"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"В истории смсок: ошибка отправки на номер 79066564234 ((от iphoneg2016.qnits.ru, по заказу №217485) Сергей, Реквизиты для оплаты в банке: БИК: 044030774 Банк: "ЮГРА" в г.Санкт-Петербурге Cчет: 40702810202000003601 ООО "Кьюнитс Трейд" ИНН: 7804541370 Назначение: за пересылку заказа №217485 Сумма: 1899 руб): 248: CYRLAT FILTER"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #" "#
let lookupRange = (testString as NSString).range(of: pattern, options: .regularExpression, range: stringRange)
if lookupRange.intersection(stringRange) != nil {
let result = regex.stringByReplacingMatches(in: testString, range: lookupRange, withTemplate: substitutionString)
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression