regex101: Teachers expiry date 19022021

1st Alternative^((0[1-9]|[12]\d|3[01])\/(0[3578]|1[02])\/((202[1-9])))$

^start of line

Group 1((0[1-9]|[12]\d|3[01])\/(0[3578]|1[02])\/((202[1-9])))

Group 2(0[1-9]|[12]\d|3[01])

1st Alternative0[1-9]

0the literal 0 (48₁₀ / 60₈ / 30₁₆)

Character Class[1-9]

1-9one character from 1 (49₁₀) to 9 (57₁₀)

2nd Alternative[12]\d

Character Class[12]

1the literal 1 (49₁₀ / 61₈ / 31₁₆)

2the literal 2 (50₁₀ / 62₈ / 32₁₆)

\da digit

3rd Alternative3[01]

3the literal 3 (51₁₀ / 63₈ / 33₁₆)

Character Class[01]

0the literal 0 (48₁₀ / 60₈ / 30₁₆)

1the literal 1 (49₁₀ / 61₈ / 31₁₆)

\/the literal / (47₁₀ / 57₈ / 2F₁₆)

Group 3(0[3578]|1[02])

1st Alternative0[3578]

0the literal 0 (48₁₀ / 60₈ / 30₁₆)

Character Class[3578]

3the literal 3 (51₁₀ / 63₈ / 33₁₆)

5the literal 5 (53₁₀ / 65₈ / 35₁₆)

7the literal 7 (55₁₀ / 67₈ / 37₁₆)

8the literal 8 (56₁₀ / 70₈ / 38₁₆)

2nd Alternative1[02]

1the literal 1 (49₁₀ / 61₈ / 31₁₆)

Character Class[02]

0the literal 0 (48₁₀ / 60₈ / 30₁₆)

2the literal 2 (50₁₀ / 62₈ / 32₁₆)

\/the literal / (47₁₀ / 57₈ / 2F₁₆)

Group 4((202[1-9]))

Group 5(202[1-9])

202the literal text 202

Character Class[1-9]

1-9one character from 1 (49₁₀) to 9 (57₁₀)

$end of line

2nd Alternative^((0[1-9]|[12]\d|30)\/(0[469]|11)\/((202[1-9])))$

^start of line

Group 6((0[1-9]|[12]\d|30)\/(0[469]|11)\/((202[1-9])))

Group 7(0[1-9]|[12]\d|30)

1st Alternative0[1-9]

0the literal 0 (48₁₀ / 60₈ / 30₁₆)

Character Class[1-9]

1-9one character from 1 (49₁₀) to 9 (57₁₀)

2nd Alternative[12]\d

Character Class[12]

1the literal 1 (49₁₀ / 61₈ / 31₁₆)

2the literal 2 (50₁₀ / 62₈ / 32₁₆)

\da digit

3rd Alternative30

30the literal text 30

\/the literal / (47₁₀ / 57₈ / 2F₁₆)

Group 8(0[469]|11)

\/the literal / (47₁₀ / 57₈ / 2F₁₆)

Group 9((202[1-9]))

$end of line

3rd Alternative^((0[1-9]|[1]\d|(2[0-8]))\/(02)\/(202[2-9]))$

4th Alternative^((0[1-9]|[12]\d|3[01])\/(01)\/((202[2-9])))$

5th Alternative^((2[0-8])\/(02)\/(2021))$

Global pattern flags

g modifier: global. Finds all matches instead of stopping after the first

m modifier: multiline. Causes ^ and $ to match the start and end of each line, not only the start and end of the string

Search reference

Regular Expression

^((0[1-9]|[12]\d|3[01])\/(0[3578]|1[02])\/((202[1-9])))$|^((0[1-9]|[12]\d|30)\/(0[469]|11)\/((202[1-9])))$|^((0[1-9]|[1]\d|(2[0-8]))\/(02)\/(202[2-9]))$|^((0[1-9]|[12]\d|3[01])\/(01)\/((202[2-9])))$|^((2[0-8])\/(02)\/(2021))$

New

11/02/2022

Regular Expressions 101

Regular Expression

Extraction