import Foundation
let pattern = #"^-?(0|[1-9]\d*)?(\.\d+)?(?<=\d)(e-?(0|[1-9]\d*))?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = #"""
3
999
-3
0
0.0
1.0
0.1
.01
-0.0000000000000000000000000000000001
2e3
-2e3
2e-3
-2e-3
1.0e0
0.1e1
.01e-1
-9.1e3
-9.1e-3
9E5
0e-11
0xff
0XFF
0x0
0xfe3
0e0
.0e-0
.0e5
.0e-5
0.0e0
0.0e123
0.0e-123
-0
-0.0
-0.0000000000000000000000000000000000
-.0
-.0000000000000000000000000000000000
1xff
0x
0x0fg3
0xf4.
.0xf
0xfe-3
-0xff
0.0xff
0xff.1
1e-
e89
.e3
001
-00.2
6.
f
-1
--1
-.1
2-
.-1
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression