import Foundation
let pattern = #"^(A(D|E|F|G|I|L|M|N|O|R|S|T|Q|U|W|X|Z)|B(A|B|D|E|F|G|H|I|J|L|M|N|O|R|S|T|V|W|Y|Z)|C(A|C|D|F|G|H|I|K|L|M|N|O|R|U|V|X|Y|Z)|D(E|J|K|M|O|Z)|E(C|E|G|H|R|S|T)|F(I|J|K|M|O|R)|G(A|B|D|E|F|G|H|I|L|M|N|P|Q|R|S|T|U|W|Y)|H(K|M|N|R|T|U)|I(D|E|Q|L|M|N|O|R|S|T)|J(E|M|O|P)|K(E|G|H|I|M|N|P|R|W|Y|Z)|L(A|B|C|I|K|R|S|T|U|V|Y)|M(A|C|D|E|F|G|H|K|L|M|N|O|Q|P|R|S|T|U|V|W|X|Y|Z)|N(A|C|E|F|G|I|L|O|P|R|U|Z)|OM|P(A|E|F|G|H|K|L|M|N|R|S|T|W|Y)|QA|R(E|O|S|U|W)|S(A|B|C|D|E|G|H|I|J|K|L|M|N|O|R|T|V|Y|Z)|T(C|D|F|G|H|J|K|L|M|N|O|R|T|V|W|Z)|U(A|G|M|S|Y|Z)|V(A|C|E|G|I|N|U)|W(F|S)|Y(E|T)|Z(A|M|W))$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression