import Foundation
let pattern = #"(?<=Code:).*Distribution\s([\d.,]+)(?=\n)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
Code: 210 - Test 1 - Distribution
267745 Vis - Branch Deposit 3/10/2021 2,000.00
468040 v- Branch Deposit 2/10/2021 1,700.00
586075 Visa 3/3/2021 555.48
502490 Vis 3/4/2021 1,835.51
403195 Vis 3/4/2021 2,033.56
500230 Vis 3/4/2021 651.29
Code: 210 - Test - Distribution 8,775.84
Code: 230 - Greenville - Distribution
853955 Clearing 2/1/2021 77.50
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression