import re
regex = re.compile(r"(?P<SYMBOLS>[\#/\-\!=()_:.\[\]])|(?P<NUMBERS>[\d])", flags=re.MULTILINE)
test_str = ("#/usr/bin/python3\n"
"from bisect import bisect_right\n\n"
"def binary_search(vector,x):\n"
" i = bisect_right(vector,x)\n"
" if i != len(vector)+1 and vector[i-1] == x:\n"
" return i-1\n"
" return -1\n"
" \n"
"def is_prime(vector,number):\n"
" return 1 if binary_search(vector,number) != -1 else 0 \n"
" \n"
"def prime_vector(num):\n"
" ret = []\n"
" for a in range(2,num+1):\n"
" if a == 2 or a == 3 or a == 5 or a == 7 or a == 11:\n"
" ret.append(a)\n"
" elif a %2 == 0 or a%3 == 0 or a%5 == 0 or a%7==0 or a%11 == 0:\n"
" continue\n"
" else:\n"
" ret.append(a)\n"
" return ret\n"
" \n"
"number = int(input())\n"
"prime = prime_vector(number)\n"
"ret = []\n"
"p = 0\n\n"
"while number:\n"
" if is_prime(prime,number):\n"
" ret.append(number)\n"
" break\n"
" elif number%prime[p] == 0:\n"
" ret.append(prime[p])\n"
" number = int(number / prime[p])\n"
" else:\n"
" p = p + 1\n"
" \n"
"for a in range((len(ret))):\n"
" print(ret[a],end=\" \")\n")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html