import Foundation
let pattern = ##"^(?:[a-z][0-9a-z-.+]*:\/\/)?((?:(?:[a-z\u00a1-\uffff0-9_]+-?)*[a-z\u00a1-\uffff0-9_]+)(?:\.(?:[a-z\u00a1-\uffff0-9_]+-?)*[a-z\u00a1-\uffff0-9_]+)*(?:\.(?:[a-z0-9\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/.*)?(?:\?.*)?(?:\#.*)?$"##
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = #"""
socks://www.example.com
10.1.1.1
10.1.1.2/4
10.1.1.3/0
10.1.1.0/8
10.1.1.5/32
10.1.1.6/35
10.1.1.7/36000
10.1.1.8/abcd
10.1.1.9-10.1.1.10
user:pass@zxuz.com
user@proxy.brew.opendnstest.com/customBlockUserInfo
user:@proxy.brew1.opendnstest.com/customBlockUserInfo
user:password@proxy.brew2.opendnstest.com/customBlockUserInfo
ftp://cnn.example.com&story=breaking_news@foobar.com/top_story.htm
foo.com:8080/bar/baz
asdfasdf.com/foo/b%20ar
https://example.com/archive/*/http://somesite.com
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression