re = /^(?:3[01]|[12][0-9]|0?[1-9])([\-\/.])(0?[1-9]|1[1-2])\1\d{4}$/m
str = '12.05.2022'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html