import Foundation
let pattern = #"([^\\}<]{3}|][^]]|^).?[$PG]$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
The next answer has to match the following strings:
PPCG
^P
^[P^]P
[^?][PG]$
(?<!\\..)(?!]).$
^[\w^]*$|!|]P|G]\$$
!|[^?]P(CG|G..)?$
[^])]\$|^\^?P|P.\].$
([.$?]|G\])\$$|^\^?P|\]P$
([P.$?]\$|[]^]P|G\]\$|CG)$
!|((G.|P|\.)\$|[^?]P|CG)$
^[(!P]|G..$|]..\||[^?]P$
^.{3,23}[.-~]..\$$|[^P?][PG]$
And fail on these strings:
[PPCG]
^[P\^]
[^\]]$
^\^?P
[^?][PG]$|<|PG
^[^\\|]*(\\\\)+[^\\|]*[^\]]$
^(.{,4}|.{9}|.{16,19}|.{5}P)$
^[^?]*[PG]$|[?$].*\$$
^[^[]P|]P|(G]|[.])\$$
\..$|!|\|G|^[\^P]P|P\^|G.\$$
...\^.P|^!|G]\$$|w|<!|^\^?P
([^\\}<]{3}|][^]]|^).?[$PG]$
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression