const regex = /\["([A-Z]*\d+)"/g;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('\\["([A-Z]*\\d+)"', 'g')
const str = `",[[3,"bus.png",null,"Bus",[["https://maps.gstatic.com/mapfiles/transit/iw2/b/bus.png",0,[15,15],null,0]]]],[[null,null,null,null,"0x31da18325b415901:0xeb661015c651c24a",[[5,["48",1,"#ffffff"]]]],[null,null,null,null,"0x31da19f34e04d59b:0x5758ef6990938b",[[5,["61",1,"#ffffff"]]]],[null,null,null,null,"0x31da1a5b8b75c379:0x6a13e189555f9fab",[[5,["95",1,"#ffffff"]]]],[null,null,null,null,"0x31da1a16ea23bf95:0xd7c90f15535c2b9f",[[5,["106",1,"#ffffff"]]]],[null,null,null,null,"0x31da10a7613d616f:0xf1f61ffeac2ea8a4",[[5,["970",1,"#ffffff"]]]],[null,null,null,null,"0x31da1a0bd6262d0b:0xfbd5d2bfd7a1252",[[5,["NR8",1,"#ffffff"]]]]],null,0,"5"]]],["http://www
48, 61,95,106,970,NR8`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions