import Foundation
let pattern = #"(?P<time>\d\d:\d\d:\d\d.\d{3})\s(?P<date>\d\d/\d\d/\d\d)\s(?P<sno>\d{10})\s(?P<status>\w{1,2}).*?-\s*(?P<bcode>No_barcode|\W{20})(?:\s+(?P<type>\w{3}))?(?:.*?(?P<pr>Pt.*?\d*[.]?\d*\s[a-z]+))?(?:\s{1,3}(?P<fl>FL.*?\d*[.]?\d*\s[a-z]+))?"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
95031B2 R C01 N1 P93 R-- 12:39:18.540 08/05/20 0000002802 R - No_barcode FLC F LR 7.673353 sccm Pt 25.288202 psig FL 536.651917 sccm EDC 0.000000 sccm PQ 7.668324 sccm QF 536.289246 sccm QP 25.287605 psig LLQ -0.109524 sccm HLQ 4.440174 sccm CLF 1.429953 sccm MF 0.000000 sccm LF 100.000015 sccm MQF 0.000000 sccm LQF 100.000015 sccm FPR 25.290846 psig
5102060 R C01 N1 P93 R-- 12:38:52.140 08/05/20 0000002801 FO - No_barcode
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression