import re
regex = re.compile(r"(?:(?:[a-f0-9]*)?:){1,7}[a-f0-9]*|(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)", flags=re.MULTILINE | re.IGNORECASE)
test_str = ("[::1]\n"
"[:a:1]\n"
"[:bh:lh:1]\n"
"[1:1:fEd1:1:abdc:1]\n"
"[::ffff:192.0.2.128]\n"
"[0000:0000:0000:0000:0000:0000:0000:0001]\n"
"[2001:0db8:0000:0000:0000:ff00:0042:8329]\n"
"[2001:db8:0:0:0:ff00:42:8329]\n"
"[2001:db8::ff00:42:8329]\n"
"[2001:0db8:0000:0000:0000:ff00:0042:8329]\n\n"
"::1\n"
":a:1\n"
":bh:lh:1\n"
"1:1:fEd1:1:abdc:1\n"
"::ffff:192.0.2.128\n"
"0000:0000:0000:0000:0000:0000:0000:0001\n"
"2001:0db8:0000:0000:0000:ff00:0042:8329\n"
"2001:db8:0:0:0:ff00:42:8329\n"
"2001:db8::ff00:42:8329\n"
"2001:0db8:0000:0000:0000:ff00:0042:8329\n\n"
"United Kingdom , London\n"
"IP: 91.149.202.91\n"
"IPv6: 2605:e440:8::2:1b\n"
"http://91.149.202.91/1000MB.test\n"
"http://[2605:e440:8::2:1b]/1000MB.test\n")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html