import Foundation
let pattern = #"(O[KZ]-\d+):([a-zA-Z0-9 ]+):([a-zA-Z0-9 ]+):([a-zA-Z0-9 ]+):([a-zA-Z0-9 ]+):([a-zA-Z0-9 ]+):([a-zA-Z0-9 ]+)(?= O[KZ]|$)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
"Team","Members"
Team 1,OK-10:Jason:Jones:ID No:00000000:male:my notes
Team 2,OK-10:Mike:James:ID No:00000001:male:my notes OZ-09:John:Rick:ID No:00000002:male:my notes
Team 3,OK-08:Michael:Knight:ID No:00000004:male:my notes2 OK-09:Helen:Rick:ID No:00000005:female:my notes3 OZ-10:Jane:James:ID No:00000034:female:my notes23 OK-09:Mary:Jane:ID No:00000023:female:my notes46
O[KZ]-\d+:(?:[^:]+:){5}.*?(?= O[KZ]|$)
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression