import Foundation
let pattern = ##"""
^ # Start of line
(?: # Start of the alternation group
(?=.*\d)(?=.*[a-z])(?=.*[A-Z]) # Conditions 1, 2, 3
|
(?=.*\d)(?=.*[a-z])(?=.*[!@#$%^&*()_+]) # Conditions 1, 2, 4
|
(?=.*\d)(?=.*[A-Z])(?=.*[!@#$%^&*()_+]) # Conditions 1, 3, 4
|
(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%^&*()_+]) # Conditions 2, 3, 4
|
(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%^&*()_+]) # Conditions 1, 3, 4
)
.* # The line itself is matched
$ # Up to the end of line
"""##
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .allowCommentsAndWhitespace])
let testString = ##"""
12345678
adfghj
AASDFGHJ
!@#$%^&
1234as
1234ASDF
1345!#$%
asdfg!@#$
ASDFGB!#$$
SSRasd
Goodone123
G00done!@#
1@a
Aa1
must have 3 of 4:
Contain Numbers
Contain a-z
Contain A-Z
contain special characters !@#$%^&*()_+
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression