re = /(0?[1-9]|1[012])\/(0?[1-9]|[12][0-9]|3[01])\/((19|20)\d\d)/
str = '09/10/2010'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html