re = /(?<![\/0-9])(\+\d{1,2}\s)?\(?\d{3}\)?[\s.-]?\d{2,3}[\s.-]?\d{3}/mi
str = '23242424 242424242 24242424424 2424244242 242 24242424/1212121212 1 05454545454 5454045454 0115545454 /454545454
23242424 242424242 24242424424 2424244242 242 24242424/1212121212 1 05454545454 5454045454 0115545454 /454545454'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html