import Foundation
let pattern = #"(?ms)\s-\s(?<Service>[^-]*).*oozie(\<[^\>]*\>){2}(?<oozie>[^\<]*)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = ##"""
MIME-Version: 1.0 Content-Disposition: inline Subject: INFO - Services are in Maintenance Mode over 2 hours -- AtWork-CIW-E1 Content-Type: text/html <font size=3 color=black>Hi Team,</br></br>Please find below servers which are in maintenance mode for more than 2 hours; </br></br></font> <table border=2> <TR bgcolor=#D6EAF8><TH colspan=2>Cluster Name: AtWork-CIW-E1</TH></TR> <TR bgcolor=#D6EAF8><TH colspan=1>Service</TH><TH colspan=1>Maintenance Start Time in MST</TH></TR>
<TR bgcolor=#FFB6C1><TH colspan=1>oozie</TH><TH colspan=1>Mon Oct 16 07:29:46 MST 2023</TH></TR> </table> <font size=3 color=black></br> Script Path:/amex/ansible/maintenance_mode_service</font> <font size=3 color=black></br></br>Thank you,</br>BDP Spark Support Team</font>
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression