import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "(at)(?:.(?!at))*(.*)\\s([A-Z]{1,2}[0-9][A-Z0-9]? [0-9][ABD-HJLNP-UW-Z]{2})";
final String string = "The AGM will be held at the Company's registered office at Unity House, Telford Road, Basingstoke, Hampshire, RG21 6YJ on 13 January 2016 at 10.00 a.m.\n\n"
+ "The Company announces that its 2016 Annual General Meeting will be held on 11 February 2016 at 10.00 a.m. at Hangar 89, London Luton Airport, Luton, Bedfordshire, LU2 9PF.";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html