import Foundation
let pattern = #"^(0|62|\+62)(8[1-35-9]\d{7,10}|2[124]\d{7,8}|619\d{8}|2(?:1(?:14|500)|2\d{3})\d{3}|61\d{5,8}|(?:2(?:[35][1-4]|6[0-8]|7[1-6]|8\d|9[1-8])|3(?:1|[25][1-8]|3[1-68]|4[1-3]|6[1-3568]|7[0-469]|8\d)|4(?:0[1-589]|1[01347-9]|2[0-36-8]|3[0-24-68]|43|5[1-378]|6[1-5]|7[134]|8[1245])|5(?:1[1-35-9]|2[25-8]|3[124-9]|4[1-3589]|5[1-46]|6[1-8])|6(?:[25]\d|3[1-69]|4[1-6])|7(?:02|[125][1-9]|[36]\d|4[1-8]|7[0-36-9])|9(?:0[12]|1[013-8]|2[0-479]|5[125-8]|6[23679]|7[159]|8[01346]))\d{5,8})"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
087887877387
027409456804
+628985986598
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression