# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"([ \t\n\r][0-9]+[.][ \t\n\r]\w+[ \t\n\r])"
test_str = ("[Event \"?\"] [Site \"?\"] [Date \"2018.04.11\"] [Round \"?\"] [White \"Bond\"] [Black \"Tor\"] [Result \"1/2-1/2\"] [ECO \"C88\"] [Annotator \"Top\"] [PlyCount \"26\"] [SourceDate \"2018.04.11\"] [SourceVersionDate \"2018.04.11\"]\n"
"1. e4 e5 2. Nf3 Nc6 3. Bb5 a6 4. Ba4 Nf6 5. O-O Be7 6. Re1 b5 7. Bb3 O-O 8. h3 Bb7 9. d3 d6 10. a3 Nb8 11. Nbd2 Nbd7 12. Nf1 Re8 13. Ng3 Bf8 1/2-1/2")
subst = "$1\\$14 "
# You can manually specify the number of replacements by changing the 4th argument
result = re.sub(regex, subst, test_str, 0)
if result:
print (result)
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html