re = /(^\s*(?P<att_name>[^:\n]+):\s*?(?P<att_value>.+)?)$/mx
str = 'Certificate:
Data:
Version: 1 (0x0)
Serial Number: 1 (0x1)
Signature Algorithm: sha256WithRSAEncryption
Issuer: O=NetApp Inc,, CN=Mediator CA
Validity
Not Before: Jan 14 15:28:02 2020 GMT
Not After : Jan 13 15:28:02 2021 GMT
Subject: O=NetApp Inc,, CN=Mediator Server
Subject Public Key Info:
Public Key Algorithm: rsaEncryption
Public-Key: (2048 bit)
Modulus:
00:e3:dd:79:69:41:23:85:6b:d1:3f:74:0e:1d:c2:
13:d1:54:c9:17:cb:8f:d9:b3:87:1d:26:dd:09:ba:
eb:53:3d:17:cf:f6:c4:71:14:61:3c:55:85:a2:59:
78:c9:8f:0f:9e:b2:c9:73:06:13:5c:7b:55:35:18:
30:86:3c:f3:a1:69:8a:b6:fd:17:45:ab:0c:64:76:
'
subst = '---\\n\\3'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html