re = /(?:([^;]*);){23}/m
str = '57423543521;314743352134;Source;Tue Apr 02 12:32:44 BST 2019;ELIGIBILITY;ABC345;MyChannel;DUMBRE;1;RR87835;NM;2019-04-02T07:20:00.000Z;VV;;;M;N;XCB234657;;24234SDF4435345;MrNitinDumbre;N;N;DFD4546;Adult;;MYTICKET;4535435435;;657657655;PP;N;Y;;Y;;N;;;Unconfirmed;;;Not Performed;OK;;Not Known'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html