import Foundation
let pattern = #"""
\[\ (RUNNING|STOPPED)\ \]
(.+?)
(?:\[Pid:\ (\d+)\]|$)
"""#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .allowCommentsAndWhitespace])
let testString = #"""
I want to extract the words between the two bracket "blocks" and also the word in first brackets (RUNNING or STOPPED).
Example (extract the bolded part):
[ RUNNING ] My First Application [Pid: 4194]
[ RUNNING ] Second app (some data) [Pid: 5248]
[ STOPPED ] Logger App
So, as you can see, the [Pid: X] part is optional. I can write the regex as follows:
\[\s+(RUNNING|STOPPED)\s+\]\s+([^\[]+).*
and it will work. But this would fail if App name would contain the '[' character. I tried the following, but it won't work:
\[\s+(RUNNING|STOPPED)\s+\]\s+(?!\[Pid)+.*
My idea was to match any words/characters that are not starting with "[Pid", but I guess this would match any words that are not followed by "[Pid".
Is there any way to do exactly that: Match any word that is not "[Pid", i.e. match the part until first appearing of "[Pid" substring?
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression