import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = #"(?:^|\s)(((?:\+|0{2})(?:49|43|33)[-\. ]?|0)([1-9]\d{1,2}[-\. ]?|\([1-9]\d{1,2}\)[-\. ]?)(\d{6,9}|\d{2,3}[-\. ]\d{4,6}))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
+33 100 000 0000
000-000-0000
000 000 0000
000.000.0000
12000-000-000012
12000 000 000012
12000.000.000012
0049-000-0000
000 000 0000
000.000.0000
(000)000-0000
(000)000 0000
(000)000.0000
(000) 000-0000
(000) 000 0000
(000) 000.0000
12(000)000-000012
12(000)000 000012
12(000)000.000012
12(000) 000-000012
12(000) 000 000012
12(000) 000.000012
000-0000
000 0000
000.0000
0000000
(100)0000000
12000-000012
12000 000012
12000.000012
12000000012
12(000)000000012
+28 100 000 0000
+33 000 000 0000
+33 100 000 0000
+49 100 000 0000
+43 100 000 0000
+43.100.000.0000
+43-100-000-0000
+43 100 000 0000
+43.100.000.0000
+43-100-000-0000
+433 100 000 0000
+433.100.000.0000
+433-100-000-0000
+433000000000
0043 1000000000
0043 100000000000023
0043 100000
0043 100000000
0043 100 00 00000
0043 100 000 0000
0043-100-000-0000
00431000000000
0000-000-000-0000
00000000000000
+43 (100)000 0000
0043 (100)000-0000
0043(100)000-0000
0000 (100)000-0000
0000(100)000-0000
+43 (100) 000 0000
0043 (100) 000-0000
0043(100) 000-0000
0000 (100) 000-0000
0000(100) 000-0000
+43 (10)000 0000
0043 (10)000-0000
0043(10)000-0000
0000 (10)000-0000
0000(10)000-0000
+43 (10) 000 0000
0043 (10) 000-0000
0043(10) 000-0000
0000 (10) 000-0000
0000(10) 000-0000
0662 874278
0676 7359567
0343545435343
06700000023
12+43 100 000 000012
12+43.100.000.000012
12+43-100-000-000012
12+43100000000012
120043 100000000012
120043-100-000-000012
120043100000000012
12+43 (100)000 000012
120043 (100)000-000012
120043(100)000-000012
+49 10 000000
(000) 0000-0000
(0000) 0000-0000
(00000) 000-0000
(030000) 00-0000
01200-0000000
0137-000 0000000
01500-0000000
0160-0000000
0170-0000000
032-000000000
0700-0000000
0800-0000000
0900-0-000000
0000000000000
0000000000000
120000000000000
120000000000000
+00+00 000 0000
2013 175000km
019 55000km
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression